blob: e575c4ca1df13a090a0c75abbf38884a22841fe3 [file] [log] [blame]
<html>
<head>
<meta charset="utf-8" />
<script>
if (window.testRunner)
testRunner.dumpAsText();
</script>
</head>
<body>
<p>
This test ensures that combining marks apper over the previous (or next) character by comparing the length of
words (one has marks, and the other doesn't have marks).
</p>
<div style="font-family: arial; text-rendering: optimizeLegibility;">
<span id="reference1">test проверка</span>
</div>
<div style="font-family: arial;">
<span id="target1">te&#768;st прове&#768;рка</span>
</div>
<div>
<span id="reference2">خانه</span>
</div>
<div>
<span id="target2">خانهٔ</span>
</div>
<div id="result"></div>
<script>
var reference1 = document.getElementById('reference1');
var target1 = document.getElementById('target1');
var reference2 = document.getElementById('reference2');
var target2 = document.getElementById('target2');
var result = document.getElementById('result');
// Ignore a slight diff of the width between target and reference.
var diff1 = Math.abs(reference1.offsetWidth - target1.offsetWidth);
var diff2 = Math.abs(reference2.offsetWidth - target2.offsetWidth);
if (diff1 < 2 && diff2 < 2)
result.innerHTML = 'PASS. The length of targets and references are the same.<br />'
else
result.innerHTML = 'FAIL<br />' +
'reference1.offsetWidth = ' + reference1.offsetWidth + '<br />' +
'target1.offsetWidth = ' + target1.offsetWidth + '<br />' +
'reference2.offsetWidth = ' + reference2.offsetWidth + '<br />' +
'target2.offsetWidth = ' + target2.offsetWidth + '<br />'
</script>
</body>
</html>