| # Copyright (C) 2011 Google Inc. All rights reserved. |
| # |
| # Redistribution and use in source and binary forms, with or without |
| # modification, are permitted provided that the following conditions are |
| # met: |
| # |
| # * Redistributions of source code must retain the above copyright |
| # notice, this list of conditions and the following disclaimer. |
| # * Redistributions in binary form must reproduce the above |
| # copyright notice, this list of conditions and the following disclaimer |
| # in the documentation and/or other materials provided with the |
| # distribution. |
| # * Neither the name of Google Inc. nor the names of its |
| # contributors may be used to endorse or promote products derived from |
| # this software without specific prior written permission. |
| # |
| # THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS |
| # "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT |
| # LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR |
| # A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT |
| # OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, |
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| # LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, |
| # DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY |
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| # OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. |
| |
| |
| """Checks WebKit style for the watchlist file.""" |
| |
| |
| from webkitpy.common.watchlist.watchlistparser import WatchListParser |
| |
| |
| class WatchListChecker(object): |
| |
| """Processes the watch list for checking style.""" |
| |
| def __init__(self, file_path, handle_style_error): |
| self._handle_style_error = handle_style_error |
| self._handle_style_error.turn_off_line_filtering() |
| |
| def check(self, lines): |
| def log_to_style_error(message): |
| # Always report line 0 since we don't have anything better. |
| self._handle_style_error(0, |
| 'watchlist/general', 5, |
| message) |
| |
| WatchListParser(log_error=log_to_style_error).parse('\n'.join(lines)) |
