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| * The Original Code is JavaScript Engine testing utilities. |
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| * The Initial Developer of the Original Code is Netscape Communications Corp. |
| * Portions created by the Initial Developer are Copyright (C) 2002 |
| * the Initial Developer. All Rights Reserved. |
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| * Contributor(s): pschwartau@netscape.com |
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| * |
| * |
| * Date: 31 July 2002 |
| * SUMMARY: Testing regexps containing octal escape sequences |
| * This is an elaboration of mozilla/js/tests/ecma_2/RegExp/octal-003.js |
| * |
| * See http://bugzilla.mozilla.org/show_bug.cgi?id=141078 |
| * for a reference on octal escape sequences in regexps. |
| * |
| * NOTE: |
| * We will use the identities '\011' === '\u0009' === '\x09' === '\t' |
| * |
| * The first is an octal escape sequence (\(0-3)OO; O an octal digit). |
| * See ECMA-262 Edition 2, Section 7.7.4 "String Literals". These were |
| * dropped in Edition 3 but we support them for backward compatibility. |
| * |
| * The second is a Unicode escape sequence (\uHHHH; H a hex digit). |
| * Since octal 11 = hex 9, the two escapes define the same character. |
| * |
| * The third is a hex escape sequence (\xHH; H a hex digit). |
| * Since hex 09 = hex 0009, this defines the same character. |
| * |
| * The fourth is the familiar escape sequence for a horizontal tab, |
| * defined in the ECMA spec as having Unicode value \u0009. |
| */ |
| //----------------------------------------------------------------------------- |
| var i = 0; |
| var bug = 141078; |
| var summary = 'Testing regexps containing octal escape sequences'; |
| var status = ''; |
| var statusmessages = new Array(); |
| var pattern = ''; |
| var patterns = new Array(); |
| var string = ''; |
| var strings = new Array(); |
| var actualmatch = ''; |
| var actualmatches = new Array(); |
| var expectedmatch = ''; |
| var expectedmatches = new Array(); |
| |
| |
| /* |
| * Test a string containing the null character '\0' followed by the string '11' |
| * |
| * 'a' + String.fromCharCode(0) + '11'; |
| * |
| * Note we can't simply write 'a\011', because '\011' would be interpreted |
| * as the octal escape sequence for the tab character (see above). |
| * |
| * We should get no match from the regexp /.\011/, because it should be |
| * looking for the octal escape sequence \011, i.e. the tab character - |
| * |
| */ |
| status = inSection(1); |
| pattern = /.\011/; |
| string = 'a' + String.fromCharCode(0) + '11'; |
| actualmatch = string.match(pattern); |
| expectedmatch = null; |
| addThis(); |
| |
| |
| /* |
| * Try same thing with 'xx' in place of '11'. |
| * |
| * Should get a match now, because the octal escape sequence in the regexp |
| * has been reduced from \011 to \0, and '\0' is present in the string - |
| */ |
| status = inSection(2); |
| pattern = /.\0xx/; |
| string = 'a' + String.fromCharCode(0) + 'xx'; |
| actualmatch = string.match(pattern); |
| expectedmatch = Array(string); |
| addThis(); |
| |
| |
| /* |
| * Same thing; don't use |String.fromCharCode(0)| this time. |
| * There is no ambiguity in '\0xx': it is the null character |
| * followed by two x's, no other interpretation is possible. |
| */ |
| status = inSection(3); |
| pattern = /.\0xx/; |
| string = 'a\0xx'; |
| actualmatch = string.match(pattern); |
| expectedmatch = Array(string); |
| addThis(); |
| |
| |
| /* |
| * This one should produce a match. The two-character string |
| * 'a' + '\011' is duplicated in the pattern and test string: |
| */ |
| status = inSection(4); |
| pattern = /.\011/; |
| string = 'a\011'; |
| actualmatch = string.match(pattern); |
| expectedmatch = Array(string); |
| addThis(); |
| |
| |
| /* |
| * Same as above, only now, for the second character of the string, |
| * use the Unicode escape '\u0009' instead of the octal escape '\011' |
| */ |
| status = inSection(5); |
| pattern = /.\011/; |
| string = 'a\u0009'; |
| actualmatch = string.match(pattern); |
| expectedmatch = Array(string); |
| addThis(); |
| |
| |
| /* |
| * Same as above, only now for the second character of the string, |
| * use the hex escape '\x09' instead of the octal escape '\011' |
| */ |
| status = inSection(6); |
| pattern = /.\011/; |
| string = 'a\x09'; |
| actualmatch = string.match(pattern); |
| expectedmatch = Array(string); |
| addThis(); |
| |
| |
| /* |
| * Same as above, only now for the second character of the string, |
| * use the escape '\t' instead of the octal escape '\011' |
| */ |
| status = inSection(7); |
| pattern = /.\011/; |
| string = 'a\t'; |
| actualmatch = string.match(pattern); |
| expectedmatch = Array(string); |
| addThis(); |
| |
| |
| /* |
| * Return to the string from Section 1. |
| * |
| * Unlike Section 1, use the RegExp() function to create the |
| * regexp pattern: null character followed by the string '11'. |
| * |
| * Since this is exactly what the string is, we should get a match - |
| */ |
| status = inSection(8); |
| string = 'a' + String.fromCharCode(0) + '11'; |
| pattern = RegExp(string); |
| actualmatch = string.match(pattern); |
| expectedmatch = Array(string); |
| addThis(); |
| |
| |
| |
| |
| //------------------------------------------------------------------------------------------------- |
| test(); |
| //------------------------------------------------------------------------------------------------- |
| |
| |
| |
| function addThis() |
| { |
| statusmessages[i] = status; |
| patterns[i] = pattern; |
| strings[i] = string; |
| actualmatches[i] = actualmatch; |
| expectedmatches[i] = expectedmatch; |
| i++; |
| } |
| |
| |
| function test() |
| { |
| enterFunc ('test'); |
| printBugNumber (bug); |
| printStatus (summary); |
| testRegExp(statusmessages, patterns, strings, actualmatches, expectedmatches); |
| exitFunc ('test'); |
| } |