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JSTests
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stress
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out-of-bounds-sane-chain-need-their-own-heap-location.js
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const
a0
=
[
0
];
function
foo
()
{
for
(
let i
=
1
;
i
<
100
;
i
++)
{
a0
[
i
];
a0
[
i
]
=
undefined
;
let x
=
[];
for
(
let j
=
0
;
j
<
20
;
j
++)
{}
}
}
for
(
let i
=
0
;
i
<
10000
;
i
++)
{
foo
();
}