<!DOCTYPE html>
<html>
<head>
<script>
if (window.testRunner) {
    testRunner.dumpAsText();
    testRunner.setCanOpenWindows(true);
    testRunner.overridePreference('WebKitSupportsMultipleWindows', false);
    testRunner.waitUntilDone();
}

function click(elmt)
{
    var event = document.createEvent('MouseEvent');
    event.initEvent('click', true, true);
    elmt.dispatchEvent(event);
}

function runTest()
{
    if (window.testRunner)
        testRunner.initialWindowCount = testRunner.windowCount();
    var button = document.getElementById("post-button");
    click(button);
    if (window.testRunner) {
        start = new Date();
        testInterval = setInterval(checkIfDone, 1);
    }
}

function checkIfDone ()
{
    if (testRunner.globalFlag) {
        document.writeln('FAIL: Popup opened in a new window');
        clearInterval(testInterval);
        testRunner.notifyDone();
    } else if ((new Date() - start) > 10000) {
        document.writeln('FAIL: Popup did not open');
        clearInterval(testInterval);
        testRunner.notifyDone();
    }
}

window.addEventListener('load', runTest, true);
</script>
</head>
<body>
  You need popups to be enabled to run this test.
  <form method="post" target="_blank" action="data:text/html;charset=utf-8,<html><head><script>function test() { if (!window.testRunner) return; testRunner.globalFlag=1; if (testRunner.initialWindowCount != testRunner.windowCount()) return; document.writeln('PASS: Popup opened in the same window'); testRunner.notifyDone(); }</script></head><body onload='test()'>The test passes if this page opens in the same window</body></html>">
    <input id="post-button" type="submit" value="Click me!" />
  </form>
</body>
</html>