| description( |
| "Tests what happens when CFG simplification leads to the elimination of a set local that had a type check, and then we do a typeof on the value, which can be constant folded if the type check stays." |
| ); |
| |
| function foo(o) { |
| var x; |
| if (o.f) |
| x = o.g; |
| else |
| x = o.h; |
| return [typeof x, x - 1]; |
| } |
| |
| silentTestPass = true; |
| noInline(foo); |
| |
| for (var i = 0; i < 500; i = dfgIncrement({f:foo, i:i + 1, n:100})) { |
| var o = {f:foo}; |
| var expectedFirst; |
| var expectedSecond; |
| if (i < 450) { |
| o.g = i; |
| expectedFirst = "\"number\""; |
| expectedSecond = "" + (i - 1); |
| } else { |
| o.g = "42"; |
| expectedFirst = "\"string\""; |
| expectedSecond = "41"; |
| } |
| var result = foo(o); |
| shouldBe("result[0]", expectedFirst); |
| shouldBe("result[1]", expectedSecond); |
| } |
| |